A stone is dropped from a bridge and it reaches the ground in 4 seconds. The height of the bridge is
A
78.4m
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B
64.2m
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C
98.6m
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D
116.8m
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Solution
The correct option is A78.4m From the question, it is clear that u=0
Time to reach the ground is t=4sec
Applying 2nd law of motion for constant acceleration, we have s=ut+12at2 ⇒h=0+12×9.8×(4)2=78.4m
Hence, height of the bridge is h=78.4m