A stone is projected from the ground with velocity 25 m/s. Two seconds later, it just clears a wall 5 m high. The angle of projection of the stone is $(g = 10 m / s e c^{2})$

$30^{\circ}$

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$45^{\circ}$

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${50.2}^{\circ}$

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$60^{\circ}$

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Solution

The correct option is A
$30^{\circ}$

For vertical upward motion $h = u t - \frac{1}{2} g t^{2}$
$5 = (25 s i n θ) \times 2 - \frac{1}{2} \times 10 \times (2)^{2}$
$\Rightarrow 25 = 50 s i n θ \Rightarrow s i n θ = \frac{1}{2} \Rightarrow θ = 30^{\circ}$

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A stone is projected from the ground with velocity 25 m/s. Two seconds later, it just clears a wall 5 m high. The angle of projection of the stone is (g=10m/sec2)

The correct option is A 30∘ For vertical upward motion h=ut−12gt2 5=(25 sin θ)×2−12×10×(2)2 ⇒25=50 sin θ⇒sin θ=12⇒θ=30∘

A stone is projected from the ground with velocity 25 m/s. Two seconds later, it just clears a wall 5 m high. The angle of projection of the stone is $(g = 10 m / s e c^{2})$

The correct option is A
$30^{\circ}$

For vertical upward motion $h = u t - \frac{1}{2} g t^{2}$
$5 = (25 s i n θ) \times 2 - \frac{1}{2} \times 10 \times (2)^{2}$
$\Rightarrow 25 = 50 s i n θ \Rightarrow s i n θ = \frac{1}{2} \Rightarrow θ = 30^{\circ}$