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Question

A stone is thrown from a point at a distance a from a wall of height b. If it just clears the wall and angle of projection is α, the maximum height attained by the stone is

A
a2sec2α4(asecαb)
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B
a2tan2α4(atanαb)
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C
a2tanα4(absecα)
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D
a2tanα4
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Solution

The correct option is B a2tan2α4(atanαb)
Equation of trajectory of the projectile is given by,
y=xtanα(gx2)2u2cos2α
Height of wall, y=b and distance between wall and point of projection, x=a, therefore
b=atanαga22u2cos2α
atanαb=ga22u2cos2α
therefore,
u2g=a22cos2α(atanαb)
Maximum height, h=u2sin2α2g
h=a2tan2α4(atanαb)

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