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Question 5
A stone is thrown in a vertically upward direction with a velocity of 5 ms1. If the acceleration of the stone during its motion is 10 ms2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

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Solution

Given initial velocity of the stone, u=5 ms1, acceleration, a=10 ms2 (negative as it is in vertically downward direction)
At highest point, final velocity, v=0
From third equation of motion, v2u2=2as
0252=2×10×s
Therefore, height attained by the stone, s=2520=1.25 m
Also we know that final velocity, v = u + at
or, time, t=vua
t=0510
=0.5 s

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