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Question

A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?


  1. 0.49 N vertically downwards

  2. 0.49 N vertically upwards

  3. 0.98 N vertically downwards

  4. 9.8 N vertically downwards


Solution

The correct option is A

0.49 N vertically downwards


F=m×g=0.05×9.8=0.49N,downwards

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