A stone of mass 0-05 kg is thrown vertically upwards- What is the direction and magnitude of net force on the stone during its upward motion-A- 0-49 N vertically downwardsB- 0-49 N vertically upwardsC- 0-98 N vertically downwardsD- 9-8 N vertically downwards

F = m × g = 0.05 × 9.8 = 0.49 N, downwards nbsp; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Second Law of Motion

A stone of ma...

Question

A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

0.98 N vertically downwards

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.49 N vertically upwards

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9.8 N vertically downwards

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.49 N vertically downwards

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
0.49 N vertically downwards

$F = m \times g = 0.05 \times 9.8 = 0.49 N, d o w n w a r d s$

Suggest Corrections

Similar questions

Q. A stone of mass

0.5 k g

is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

Q. A pebble of mass

0.05 k g

is thrown vertically upwards. Give the direction and magnitude of the net force on the pebble,
(a) during its upward motion,
(b) during its downward motion,
(c) at the highest point where it is momentarily at rest. Do your answers change if the pebble was thrown at an angle of

45^{o}

with the horizontal direction?
Ignore air resistance.

A body of mass 1 kg is thrown vertically up with an initial speed of 15 ms-1. What is the magnitude and direction of the force due to gravity acting on the body when it is at the highest point ?

Q. A body of mass

1 k g

is thrown vertically upwards up with an intial speed of

5 m s^{- 1}

. What is the magnitude and direction of force due to gravity acting on the body when is at its highest point

Join BYJU'S Learning Program

A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

The correct option is D 0.49 N vertically downwards F=m×g=0.05×9.8=0.49N,downwards

The correct option is D
0.49 N vertically downwards

$F = m \times g = 0.05 \times 9.8 = 0.49 N, d o w n w a r d s$