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Question
A stone of mass 500g is thrown vertically upwards with a velocity of 15ms−1. Calculate the potential energy at the greatest height.
A stone of mass 500g is thrown vertically upwards with a velocity of 15ms−1. Calculate the potential energy at the greatest height.
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Solution
The correct option is C 56.25J
Kinetic Energy, K.E=0.5×m×v2
K.E=0.5×0.5×15×15=56.25J
As it has 56.25 J at the initial point as total energy, at some point X,Potential Energy(P.E.) is maximum.
Total energy=P.E.+K.E.
56.25=P.E.+K.E.
As energy is conserved total energy at point X also must be 40 J.For P.E to be maximum K.E. must be zero.
Hence P.E.=56.25J
We can come to the conclusion that potential energy will have the maximum value at maximum height.
Kinetic Energy, K.E=0.5×m×v2
K.E=0.5×0.5×15×15=56.25J
As it has 56.25 J at the initial point as total energy, at some point X,Potential Energy(P.E.) is maximum.
Total energy=P.E.+K.E.
56.25=P.E.+K.E.
As energy is conserved total energy at point X also must be 40 J.
For P.E to be maximum K.E. must be zero.
Hence P.E.=56.25J
We can come to the conclusion that potential energy will have the maximum value at maximum height.
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