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Law of Conservation of Energy

A stone of ma...

Question

A stone of mass m kg is whirled in a vertical circle of radius 20 cm. The difference in the kinetic energies at the lowest and the topmost positions is-

A

4 mg joules

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B

0.4 mg joules

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C

40 mg joules

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D

Sufficient data not available

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Solution

The correct option is A 0.4 mg joules
KE lost $=$ PE gained
$= m g (2 R) = m g (2 \times 0.2) = 0.4 m g$

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