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Derivation of Position-Velocity Relation by Graphical Method

A stone throw...

Question

A stone thrown vertically upwards takes 6s to reach the maximum height , 1) Calculate the initial velocity , 2)Maximum height attained by the stone. [g=10m/s(square)]

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Solution

Dear student,
$A t m a x i m u m h e i g h t v = 0 v = u - g t o r u = g t u = 10 \times 6 u = 60 m / s$

$S = u t - 0.5 g t^{2} S = 60 \times 6 - 0.5 \times 10 \times 36 S = 360 - 180 S = 180 m$

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Standard IX Physics

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