Question

A stone thrown vertically upwards takes 6s to reach the maximum height , 1) Calculate the initial velocity , 2)Maximum height attained by the stone. [g=10m/s(square)]

Answer 1

Dear student,
$$\begin{gathered} Atmaximumheightv=0 \\ v=u-gt \\ oru=gt \\ u=10\times 6 \\ u=60m/s \end{gathered}$$

$$\begin{gathered} S=ut-0.5g{t}^2 \\ S=60\times 6-0.5\times 10\times 36 \\ S=360-180 \\ S=180m \end{gathered}$$

regards