Question

A stone which has a mass of $12g$ and a density of $3gc{m}^{-3}$, is lowered into $20c{m}^3$ of water in a measuring cylinder. What will be the new reading on the measuring cylinder ?

• A. $20c{m}^3$
• B. $24c{m}^3$
• C. $40c{m}^3$
• D. $16c{m}^3$

Answer 1

The correct option is B $24c{m}^3$

Answer is B.
The volume of the stone is equal to the volume of the water increased in the measuring cylinder.

The volume of the stone is calculated from the formula Volume =Mass/Density.

In this case, the Mass = 12 g and Density = $3g{cm}^3$.

Volume = 12/3 = $4{cm}^3$.

The actual volume of liquid in the measuring cylinder is $20{cm}^3$.

So, the increase in volume will show a new reading of $20{cm}^3+4{cm}^3=24{cm}^3$.

Hence, the new reading on the measuring cylinder is $24{cm}^3$.