A storage battery is connected to a charger for charging with a voltage of $12.5$ Volts. The internal resistance of the storage battery is $1 Ω$ . When the charging current is $0.5$ A, the emf of the storage battery is

13

Volts

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12.5

Volts

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12

Volts

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11.5

Volts

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Solution

The correct option is B $12$ Volts
Resistance of the charger,
$R = \frac{V}{I}$
$R = \frac{12.5}{0.5} = 25 Ω$
Now,
$E = I R = \frac{V}{R + r} (R)$
$E = \frac{12.5}{25 + 1} (25) = (0.48) (25) = 12 V$

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A storage battery is connected to a charger for charging with a voltage of 12.5 Volts. The internal resistance of the storage battery is 1Ω. When the charging current is 0.5 A, the emf of the storage battery is

The correct option is B 12 VoltsResistance of the charger,R=VIR=12.50.5=25ΩNow,E=IR=VR+r(R)E=12.525+1(25)=(0.48)(25)=12V

A storage battery is connected to a charger for charging with a voltage of $12.5$ Volts. The internal resistance of the storage battery is $1 Ω$ . When the charging current is $0.5$ A, the emf of the storage battery is

The correct option is B $12$ Volts
Resistance of the charger,
$R = \frac{V}{I}$
$R = \frac{12.5}{0.5} = 25 Ω$
Now,
$E = I R = \frac{V}{R + r} (R)$
$E = \frac{12.5}{25 + 1} (25) = (0.48) (25) = 12 V$