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Standard X

Physics

Ampere's Experiment

A straight cu...

Question

A straight current-carrying conductor is placed in such a way that the current in the conductor flows in the direction out of the plane of the paper. The conductor is placed between two poles of two magnets, as shown. The conductor will experience a force in the direction towards.

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Solution

The correct option is B $Q$
$Explanation:-$

We know that,

$\to F = i \to l \times \to B$

$\to F = i \to l^k \times (- B^i)$

$\to F = - i \to j l B = i l B (-^j)$

Hence, the direction of magnetic force on the wire is towards Q.

$Hence the correct option is B$

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A straight current-carrying conductor is placed in such a way that the current in the conductor flows in the direction out of the plane of the paper. The conductor is placed between two poles of two magnets, as shown. The conductor will experience a force in the direction towards.

The correct option is B QExplanation:-We know that,→F=i→l×→B→F=i→l^k×(−B^i)→F=−i→jlB=ilB(−^j)Hence, the direction of magnetic force on the wire is towards Q.Hence the correct option is B

The correct option is B $Q$
$Explanation:-$

We know that,

$\to F = i \to l \times \to B$

$\to F = i \to l^k \times (- B^i)$

$\to F = - i \to j l B = i l B (-^j)$

Hence, the direction of magnetic force on the wire is towards Q.

$Hence the correct option is B$