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Question

A straight line passing through the point A(-1,2) has inclination of 60°and intersects the line x+y=5 at P. FindAP

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Solution

Dear Student,

Point A-1,2 inclination 60°m=tan60°=3Eqution of line through A-1,2 and slope m=3 isy=mx+cy=3x+c2=-3+cc=2+3y=3x+2+33x-y=-2+3This line intersect line x+y=5 at PSo, solving these two equations we get point P23-3,8-23A-1,2 P23-3,8-23AP=23-3+12+8-23-22=23-22+6-232=43-12+43-32=23-12+-323-12=23-121+3=243-12=43-1 units

Regards

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