Question

A string of length L and mass M is lying on a horizontal table. A force F is applied at one of its ends. Tension in the string at a distance y from the end at which the force applied is:

• A. $Zero$
• B. $F$
• C. $\frac{F(L-Y)}{L}$
• D. $\frac{F(L-Y)}{M}$

Answer 1

The correct option is C

$\frac{F(L-Y)}{L}$

$a=\frac{F}{M}F-T=\frac{M}{L}yaF-T=\frac{M}{L}y\frac{F}{M}F-T=F\frac{y}{L}T=F-\frac{Fy}{L}T=F[1-\frac{y}{L}]=T=F\left[\frac{L-y}{L}\right]InRodL\left(m\right)\to M1\left(m\right)\to \frac{M}{L}(L-y)m\to \frac{M}{L}[L-y]y\left(m\right)\to \frac{M}{L}y$