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Question

A string of length L is fixed at one end and carries a mass M at the other end. The string makes 2π revolutions per second around the vertical axis through the fixed end as shown in the figure, then tension in the string is


A
ML
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B
2 ML
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C
4 ML
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D
16 ML
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Solution

The correct option is D 16 ML
Tsinθ = Mω2R ...(i)
Tsinθ = Mω2Lsinθ ...(ii)

From (i) and (ii)
T = Mω2L
= M4π2n2L
= M4π2 (2π)2L
= 16 ML
Why this question?
Note:For the conical pendulum, the horizontal component of tension provides the centripetal force while the vertical component balances the weight.

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