A strip footing having 1-5m width founded at a depth of 3 m below ground level in a clay soil having c- 20kN-m2- - - 0- and unit weight - - 20kN-m3 What is the net ultimate bearing capcity using Skempton-s analysis -

(d) Net ultimate bearing capcacity, q_nu= c N_c N_c = 5(1 +0.2D_f/b) For strip footing nbsp; = 5(1+ 0.2 × 3/1.5) = 7 q_nu = 20 × 7 = 140 kN/m^2 For squar ...

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Question

A strip footing having 1.5m width founded at a depth of 3 m below ground level in a clay soil having $c = 20 k N / m^{2}, ϕ = 0^{\circ} a n d u n i t w e i g h t γ = 20 k N / m^{3}$ What is the net ultimate bearing capcity using Skempton's analysis ?

30 k N / m^{2}

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60 k N / m^{2}

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100 k N / m^{2}

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140 k N / m^{2}

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Solution

The correct option is D $140 k N / m^{2}$
(d) Net ultimate bearing capcacity,
$q_{n u} = c N_{c}$

$N_{c} = 5 (1 + 0.2 D_{f} / b)$

For strip footing

$= 5 (1 + 0.2 \times 3 / 1.5) = 7$

$q_{n u} = 20 \times 7 = 140 k N / m^{2}$

For square footing or circular footing,

$N_{c} = 6 (1 + 0.2 D_{f} / b)$

For rectangular footing,
$N_{c} = 5 (1 + 0.2 D_{f} / b) (1 + 0.2 b / L)$

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A strip footing having 1.5m width founded at a depth of 3 m below ground level in a clay soil having c=20kN/m2, ϕ=0∘ and unit weight γ=20kN/m3 What is the net ultimate bearing capcity using Skempton's analysis ?

The correct option is D 140kN/m2(d) Net ultimate bearing capcacity, qnu=c Nc Nc=5(1+0.2Df/b) For strip footing =5(1+0.2×3/1.5)=7 qnu=20×7=140kN/m2 For square footing or circular footing, Nc=6(1+0.2Df/b) For rectangular footing, Nc=5(1+0.2Df/b)(1+0.2b/L)

A strip footing having 1.5m width founded at a depth of 3 m below ground level in a clay soil having $c = 20 k N / m^{2}, ϕ = 0^{\circ} a n d u n i t w e i g h t γ = 20 k N / m^{3}$ What is the net ultimate bearing capcity using Skempton's analysis ?