A student got twice as many sums wrong as he got right. If he attempted $48$ sums in all, how many did he solve correctly?

12

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16

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18

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24

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Solution

The correct option is D $16$
Suppose the boy got $x$ sums right and $2 x$ sums wrong.
Then, $x + 2 x = 48 \Leftrightarrow 3 x = 48 \Leftrightarrow x = 16$ .

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A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly?

The correct option is D 16Suppose the boy got x sums right and 2x sums wrong.Then, x+2x=48⇔3x=48⇔x=16.

A student got twice as many sums wrong as he got right. If he attempted $48$ sums in all, how many did he solve correctly?

The correct option is D $16$
Suppose the boy got $x$ sums right and $2 x$ sums wrong.
Then, $x + 2 x = 48 \Leftrightarrow 3 x = 48 \Leftrightarrow x = 16$ .