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Electrochemical Series

A student mad...

Question

A student made the following observations in the laboratory.

(i) Clean copper metal did not react with 1 molar $P b (N O_{3})_{2}$ solution
(ii) Clean lead metal dissolved in a 1 molar $A g N O_{3}$ solution and crystals of Ag metal appeared
(iii) Clean silver metal did not react with 1 molar $C u (N O_{3})_{2}$ solution

The order of decreasing reducing character of the three metal is:

Cu, Pb, Ag

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Cu, Ag, Pb

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Pb, Cu, Ag

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Pb, Ag, Cu

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Solution

The correct option is D Pb, Cu, Ag
As Cu metal can not reduce Pb ion into solution so Pb is more reactive than Cu.

Also, Ag metal can not reduce Cu ion into solution so Cu is more reactive than Ag.

So, order of reactivity is Pb > Cu > Ag.

Suggest Corrections

Similar questions

1

P b (N O_{3})_{2}

1

A g N O_{3}

A g

1

C u (N O_{3})_{2}

A g^{+}

C u^{2 +}

3 A g (s) + 4 H N O_{3} (a q) \to 3 A g N O_{3} (a q) + N O (g) + 2 H_{2} O (l)

A g, 108 \frac{g}{m o l}

63 \frac{g}{m o l}

0.8 M H N O_{3}

2.0 g

2 A g {N O}_{3} + C u \to C u {({N O}_{3})}_{2} + 2 A g

0.17 g

A g {N O}_{3}

0.08 g

A g

A g = 107 g / m o l

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