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Question

A student named Akash is observing birds flying in the sky at the evening time. Birds are flying in the pattern like 1 in the first row, 3 in the second, 5 in the third and so on ..........
Making total 20 rows as per the figure given below, find out the total number of birds.
626371_cb3147e99d804a96b257d6d8a8828842.png

A
39
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B
400
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C
40
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D
200
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Solution

The correct option is B 400
Number of birds in first row =1
Number of birds in second row =3
Number of birds in third row =5 and so on......
So, the series 1,3,5,7,......... is making arithmetic progression
Thus, a=1
Common difference d=31=2=53
There are 20 terms n=20
Now, Sn=n2[2a+(n1)d]
=202[2(1)+(201)2]
=10[2+38]
=10×40
=400
Hence, the total no. of birds is 400.

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