wiz-icon
MyQuestionIcon
MyQuestionIcon
8
You visited us 8 times! Enjoying our articles? Unlock Full Access!
Question

A student named Akash is observing birds flying in the sky at the evening time. Birds are flying in the pattern like 1 in the first row, 3 in the second, 5 in the third and so on ..........
Making total 20 rows as per the figure given below, find out the total number of birds.
626371_cb3147e99d804a96b257d6d8a8828842.png

A
39
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
400
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
200
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 400
Number of birds in first row =1
Number of birds in second row =3
Number of birds in third row =5 and so on......
So, the series 1,3,5,7,......... is making arithmetic progression
Thus, a=1
Common difference d=31=2=53
There are 20 terms n=20
Now, Sn=n2[2a+(n1)d]
=202[2(1)+(201)2]
=10[2+38]
=10×40
=400
Hence, the total no. of birds is 400.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Where Friction?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon