A student throws his test paper up in the air (neglecting air resistance) with an initial speed of $8.10 m / s$ . How long does it take until the paper is headed downward at a speed of $3.23 m / s$ ? (in s)

1.16

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Solution

The correct option is A $1.16$
Time taken( $t$ )=Time taken to reach max height( $t_{1}$ ) + Time taken to attain the velocity in downward motion( $t_{2}$ )
$t_{1} = u / g = 8.1 / 9.8 = 0.83 s$
$t_{2} = v / g = 3.23 / 9.8 = 0.33 s$
Now, $t = t_{1} + t_{2} = 0.83 + 0.33 = 1.16 s$

Hence correct answer is option $A$

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A student throws his test paper up in the air (neglecting air resistance) with an initial speed of 8.10m/s. How long does it take until the paper is headed downward at a speed of 3.23m/s? (in s)

The correct option is A 1.16Time taken(t)=Time taken to reach max height(t1) + Time taken to attain the velocity in downward motion(t2)t1=u/g=8.1/9.8=0.83st2=v/g=3.23/9.8=0.33sNow, t=t1+t2=0.83+0.33=1.16sHence correct answer is option A

A student throws his test paper up in the air (neglecting air resistance) with an initial speed of $8.10 m / s$ . How long does it take until the paper is headed downward at a speed of $3.23 m / s$ ? (in s)