A student wants to increase the capacitance of a parallel-plate capacitor. How can he/she do this ?
A
Using smaller plates
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B
Replacing the dielectric material between the plates with one that has a smaller dielectric constant
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C
Decreasing the voltage between the plates
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D
Increasing the voltage between the plates
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E
Moving the plates closer together
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Solution
The correct option is E Moving the plates closer together We know that the capacitance, C=Aϵ0d where A be the area of plate and d be the separation between plates.
Also C=QV and the capacitance is proportional to dielectric constant.
From above information we say that only option E will give correct answer.