Question

A student wants to increase the capacitance of a parallel-plate capacitor. How can he/she do this ?

• A. Using smaller plates
• B. Replacing the dielectric material between the plates with one that has a smaller dielectric constant
• C. Decreasing the voltage between the plates
• D. Increasing the voltage between the plates
• E. Moving the plates closer together

Answer 1

The correct option is E Moving the plates closer together

We know that the capacitance, $C=\frac{A{ϵ}_0}{d}$ where A be the area of plate and d be the separation between plates.

Also $C=\frac{Q}{V}$ and the capacitance is proportional to dielectric constant.

From above information we say that only option E will give correct answer.