Question

A student was asked to solve the fraction $\frac{\frac{7}{3}+1\frac{1}{2}\times \frac{5}{3}}{2+1\frac{2}{3}}$ and his answer was $\frac{1}{4}$. By how much was his answer wrong?

• A. $1$
• B. $\frac{1}{55}$
• C. $\frac{1}{220}$
• D. $1\frac{3}{44}$

Answer 1

The correct option is D $1\frac{3}{44}$

Given exp. $=\frac{\frac{7}{3}+\frac{3}{2}\times \frac{5}{3}}{2+\frac{5}{3}}=\frac{\frac{7}{2}+\frac{5}{2}}{\frac{6+5}{3}}$
$=\frac{\frac{14+15}{6}}{\frac{11}{3}}=\frac{29}{6}\times \frac{3}{11}=\frac{29}{22}$
$\therefore$ Required answer $=\frac{29}{22}-\frac{1}{4}=\frac{58-11}{44}$
$=\frac{47}{44}=1\frac{3}{44}$