A student weighed some raisins and recorded the weight as 'x'. She then soaked the raisins in distilled water. After about 2 hours she removed the raisins, wiped them dry and weighed again and recorded that as 'y'. The percentage of water absorbed by raisins may be determined using the relationship :

\frac{y - x}{y} \times 100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{y - x}{x} \times 100

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{y - x}{x} \times \frac{1}{100}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(y - x) \times 100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{y - x}{x} \times 100$

% of water absorbed by resins $= \frac{w e i g h t o f s o a k e d r a i s i n - w e i g h t o f r a i s i n b e f o r e s o a k i n g}{w e i g h t o f r a i s i n b e f o r e s o a k i n g} \times 100$

$= \frac{y - x}{x} \times 100$

Suggest Corrections

Similar questions

Dry raisins were soaked in water for 2 hours, to determine the percentage of water absorbed by raisins. Before final weighing of swollen raisins, the extra water left on the surface of soaked raisins was removed by:

Q. a student recorded the mass of dry raisins is 6.0 g and mass of raisins after soaking them in water in 10.5 g. calculate the percentage of water absorbed by raisins.

While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements:

Mass of water in the beaker = 40 g

Mass of raisins before soaking = 5 g

Mass of raisins after soaking for 2 hours = 8 g

Mass of water left in the beaker after the experiment = 35 g

The percentage of water absorbed by raisins is:

Q. Raisins are soaked in water for determining the percentage of water absorbed by raisins. The formula used by a student for calculating the percentage of water absorbed, is:

(1)

\frac{Initial weight - Final weight}{Initial weight} \times 100

(2)

\frac{Final weight - Initial weight}{Initial weight} \times 100

(3)

\frac{Final weight - Initial weight}{Final weight} \times 100

(4)

\frac{Initial weight - Final weight}{Final weight} \times 100

Q. In the experiment for determining the percentage of water absorbed by raisins, we do the final weighing of the raisins after keeping them dipped in water for about one hour. For the accuracy of the result, the extra water from the surface of the soaked raisins is removed by :

Join BYJU'S Learning Program

The correct option is A y−xx×100% of water absorbed by resins=weight of soaked raisin−weight of raisin before soakingweight of raisin before soaking×100 =y−xx×100

The correct option is A $\frac{y - x}{x} \times 100$

% of water absorbed by resins $= \frac{w e i g h t o f s o a k e d r a i s i n - w e i g h t o f r a i s i n b e f o r e s o a k i n g}{w e i g h t o f r a i s i n b e f o r e s o a k i n g} \times 100$

$= \frac{y - x}{x} \times 100$