Question

A submarine dives from the water surface at an angle of ${30}^0$ below the horizontal, following a straight path $50m$ long. How far is the submarine then below the water surface?

• A. $50m$
• B. $\left(50m\right)/\sin {30}^0$
• C. $\left(50m\right)\sin {30}^0$
• D. $\left(50m\right)\cos {30}^0$
• E. none of those answers

Answer 1

Answer: (C)

$\left(50m\right)\sin {30}^0$

Answer (C). The vertical component is opposite the ${30}^0$ angle,

so $\sin {30}^0$ = (vertical component) / $50m$.

Vertical component = 50 sin30°