Calculate the pressure at a depth of 50m below the surface of sea. The density of sea water is 1024 $\frac{k g}{m^{3}}$ .

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Solution

Step 1: Given that:
Depth(h) = $50 m$
The density of seawater(d) = $1024 k g m^{- 3}$
Step 2: Calculation of the pressure at the given depth:
Pressure at a depth is given by,
$P = d e p t h (h) \times d e n s i t y (d) \times A c c e l e r a t i o n d u e t o g r a v i t y (g)$
Putting the values we get;
$P = 50 m \times 1024 k g m^{- 3} \times 10 m s^{- 2}$
$P = 500 \times 1024$
$P = 512000$
$P = 5.12 \times 10^{5} P a$
Thus,
The pressure at given depth is $5.12 \times 10^{5} P a$ .

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