Question

A substance of mass $49.53g$ occupies $1.5{cm}^3$ of volume. The density of the substance (in $g{cm}^{-3}$) with correct number of significant figures is :

• A. $3.3$
• B. $3.302$
• C. $3.30$
• D. $3.300$

Answer 1

The correct option is A $3.3$

Mass of the substance $m=49.53g$

Volume of the substance $V=1.5c{m}^3$

Density of the substance $d=\frac{m}{V}$

$\therefore$ $d=\frac{49.53}{1.5}=33.02gc{m}^{-3}$

As $49.53$ has four significant figures whereas $1.5$ has two significant figures.

Thus, the value of the density of the substance must have two significant figures.

Thus, the density of the substance $d=3.3gc{m}^{-3}$.