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Mole Fraction

A sugar syrup...

Question

A sugar syrup (214.2 g) contains 34.2 g sugar. Calculate molality of solution and mole fraction of each component.

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Q. 214.2 g of sugar syrup contains 34.2 g of sugar.

(i) molarity of the solution

(ii) mole fraction of sugar in the syrup.

Q. A sugar syrup (containing sugar and water only) of weight 214.2 g contains 34.2 g of sugar (

C_{12} H_{22} O_{11}

). Find the mole fraction of the sugar in the syrup.

Q. A sugar syrup of weight

214.2

34.2

(C_{12} H_{22} O_{11})

. Calculate. the molal concentration (Write your answer as 18X, where, X= molality)

Q. A sugar syrup of weight

214.2

34.2

(C_{12} H_{22} O_{11})

. Calculate the mole fraction of the sugar in the syrup.

(If the answer is X, then write

\frac{1000}{11}

234.2 g m

of sugar syrup contains

34.2 g m

of sugar. What is the molal concentration of the solution.

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