A sugar syrup (containing sugar and water only) of weight 214.2 g contains 34.2 g of sugar (C12H22O11). Find the mole fraction of the sugar in the syrup.
A
0.1×10−2
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B
9.9×10−3
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C
9.9×10−4
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D
0.1×10−3
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Solution
The correct option is B9.9×10−3 Mass of sugar in the syrup = 34.2 g
Mass of water in syrup = 214.2 - 34.2 = 180 g
Molar mass of sugar (C12H22O11) = 342 g
Number of moles = given massmolar mass
Moles of sugar = nsugar=34.2342 = 0.1 mol
Moles of water = nwater=18018 = 10 mol
Mole fraction = number of molestotal number of moles xsugar=nsugarnsugar+nwater = 0.110.1=9.9×10−3