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Question

A sulphate of a metal (A) on heating evolves two gases (B) and (C) and an oxide (D). Gas (B) turns K2Cr2O7 paper green while gas (C) forms a trimer in which there is no S-S bond. Compound (D) with conc. HCl forms a Lewis acid (E) which exists in a dimer. Compounds (A), (B), (C), (D) and (E) are respectively:

A
FeSO4, SO2, SO3, Fe2O3, FeCl3
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B
Al2(SO4)3, SO2, SO3, Al2O3, FeCl3
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C
FeS, SO2, SO3, FeSO4, FeCl3
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D
FeS, SO2, SO3, Fe2(PO4)3, FeCl2
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Solution

The correct option is A FeSO4, SO2, SO3, Fe2O3, FeCl3
Only FeSO4 gives two gases and a oxide
2FeSO4Fe2O3+SO2+SO3
SO2 turns K2Cr2O7 paper green SO3 forms trimer
D is Fe2O3
Fe2O3+6HCl2FeCl3+3H2O
FeCl3 exists in a dimer as Fe2Cl6

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