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Question

A superspeedway in New delhi has among the highest super- elevation rates of any track on the Indian Grand Prix circuit. The track requires drivers to negotiate turns with a radius of 335 m and 33∘ banking. Given this information, the coefficient of side friction required in order to allow a vehicle to travel at 320 km/h along the curve is

A
1.761
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B
0.176
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C
2.530
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D
0.253
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Solution

The correct option is A 1.761R = 335 m V = 320km/hr e+f=v2127R ⇒f=v2127R−e =3202127×335−tan33∘ =1.761 Note : While deriving the above equation, we consider 1−ef≃1 but this is not valid in this case because banking provided is very high (tan33∘=0.65). So formula used should be e+f1−ef=V2127R Which will result in f = 0.685.

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