A swimmer crosses the river along the line making an angle of 45o with the direction of flow. Velocity of the river water is 5 m/s. Swimmer takes 12 seconds to cross the river of width 60 m. The velocity of the swimmer with respect to water will be :
5 m/s
T=Bvyvy=6012=5 m/sFor 45o anglevx=vy∴vx=5 m/s¯vM=5^i+5^j¯vR=5^i∴¯vMR=¯vM−¯vR=5^j