Question

A swimmer dived off a cliff with a running horizontal leap. What must his minimum speed be just as he leaves the top of the cliff so that he will miss the ledge at the bottom which is $2m$ wide and $9m$ below the top of the cliff? (in m/s)

• A. $9$
  
• B. $1.4$
  
• C. $1$
  
• D. $2$
  

Answer 1

The correct option is B $1.4$

Time taken to cover the vertical distance of 9m$=\sqrt{\frac{2\times 9}{9.81}}=1.4s$

Min. Speed of the swimmer to miss the ledge$=\frac{2}{1.4}=1.4m/s$

Hence, correct answer is option $B$