A swimmer wants to cross a river from point $A$ to point $B$ . Line $A B$ makes an angle of $30^{\circ}$ with the flow of river. Magnitude of velocity of the swimmer is same as that of the river. The angle $θ$ with the line $A B$ sholud be $x^{\circ}$ , so that the swimmer reaches point $B .$ The value of $x$ is

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Solution

As per the question, magnitude of velocity of the swimmer is same as that of the river, i.e. both velocity vectors are of same magnitude.

Therefore, resultant would pass exactly midway through them, as shown in the figure.

Therefore, $θ = 30^{\circ}$ .

Hence, the value of $x$ is $30$ .

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A swimmer wants to cross a river from point A to point B. Line AB makes an angle of 30∘ with the flow of river. Magnitude of velocity of the swimmer is same as that of the river. The angle θ with the line AB sholud be x∘ , so that the swimmer reaches point B. The value of x is

As per the question, magnitude of velocity of the swimmer is same as that of the river, i.e. both velocity vectors are of same magnitude. Therefore, resultant would pass exactly midway through them, as shown in the figure. Therefore, θ=30∘. Hence, the value of x is 30.

As per the question, magnitude of velocity of the swimmer is same as that of the river, i.e. both velocity vectors are of same magnitude.

Therefore, resultant would pass exactly midway through them, as shown in the figure.

Therefore, $θ = 30^{\circ}$ .

Hence, the value of $x$ is $30$ .