Question

A swimming pool is $20m$ long, $15m$ wide and $3m$ deep. Find the cost of repairing the floor and wall at the rate of $Rs.25$ per square metre.

Answer 1

Given:

Length of swimming pool $\left(l\right)=20m$
Breadth of swimming pool $\left(b\right)=15m$
Height of swimming pool $\left(h\right)=3m$

We know that,

Area of floor $=\text{length}\times \text{breadth}$
$=20\times 15=300m^2$

Area of walls of swimming pool

$=2(lh+bh)$

$=2(20\times 3+15\times 3)$

$=2(60+45)$

$=2\left(105\right)$

$=210m^2$

$\therefore$ Sum of areas of floor and four walls

$=\text{area of floor}+\text{area of walls}$

$=300+210$

$=510m^2$

As, cost of repairing area of $1m^2=Rs25$
$\Rightarrow$ Cost of repairing area of $510m^2=510\times 25$
$=Rs12750$

Hence, the required cost is $Rs12750$.