A swimming pool is 250 m long and 130 m wide. 3250 cubic metres of water is pumped into it. Find the rise in the level of water.

Open in App

Solution

Volume of water = 3250 $m^{3}$
Length of pool (l) = 250 m
Breadth (b) = 130 m
$∴$ Height of water level
= $\frac{V o l u m e}{l \times b} = \frac{3250}{250 \times 130} = 0.1 m = 10 c m$

Suggest Corrections

Similar questions

A swimming pool is 260 m long and 140 m wide. If 54600 cubic metres of water Is pumped into it, find the height of the water level in it.

Q. A swimming pool is

260 m

long and

140 m

wide. If

54, 600 m^{3}

of water is pumped into it, what is the height of the water level in it?

A cylindrical container of radius 28 m and height 24 m is full of water. The water is emptied into a dry swimming pool of length 100 m and breadth 28 m. Find the rise of water level in the swimming pool.

Q. A cylindrical tank

16

m long and

23

m wide contains water. How many cubic metres of water must be rushed into it to make the surface rise by

16 \frac{2}{3}

cm ?

A swimming pool is $200 m \times 50 m$ and has an average depth of $2 m$ . By the end of a summer day, the water level drops by $2 c m$ . How many cubic metres of water is lost on the day?

Join BYJU'S Learning Program

A swimming pool is 250 m long and 130 m wide. 3250 cubic metres of water is pumped into it. Find the rise in the level of water.

Volume of water = 3250 m3 Length of pool (l) = 250 m Breadth (b) = 130 m ∴ Height of water level = Volumel×b=3250250×130=0.1m=10cm

Volume of water = 3250 $m^{3}$
Length of pool (l) = 250 m
Breadth (b) = 130 m
$∴$ Height of water level
= $\frac{V o l u m e}{l \times b} = \frac{3250}{250 \times 130} = 0.1 m = 10 c m$