Question

A swimming pool is 250 m long and 130 m wide. 3250 cubic metres of water is pumped into it. Find the rise in the level of water.

Answer 1

$$\begin{gathered} \mathrm{Length}\mathrm{of}\mathrm{the}\mathrm{pool}=250\mathrm{m} \\ \mathrm{Breadth}\mathrm{of}\mathrm{the}\mathrm{pool}=130\mathrm{m} \\ \mathrm{Also},\mathrm{it}\mathrm{is}\mathrm{given}\mathrm{that}3250{\mathrm{m}}^3\mathrm{of}\mathrm{water}\mathrm{is}\mathrm{poured}\mathrm{into}\mathrm{it}. \\ \mathrm{i}.\mathrm{e}.,\mathrm{volume}\mathrm{of}\mathrm{water}\mathrm{in}\mathrm{the}\mathrm{pool}=3250{\mathrm{m}}^3 \\ \mathrm{Suppose}\mathrm{that}\mathrm{the}\mathrm{height}\mathrm{of}\mathrm{the}\mathrm{water}\mathrm{level}\mathrm{is}h\mathrm{m}. \\ \mathrm{Then},\mathrm{volume}\mathrm{of}\mathrm{the}\mathrm{water}=\mathrm{length}\times \mathrm{breadth}\times \mathrm{height} \\ \Rightarrow 3250=250\times 130\times h \\ \Rightarrow 3250=32500\times h \\ \Rightarrow h=\frac{3250}{32500}=0.1\mathrm{m} \\ \therefore \mathrm{The}\mathrm{water}\mathrm{level}\mathrm{in}\mathrm{the}\mathrm{tank}\mathrm{will}\mathrm{rise}\mathrm{by}0.1\mathrm{m}. \end{gathered}$$