CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A synchronous motor improves the power factor of a 300kW load from 0.6 lagging to 0.8 lagging and simultaneously the motor carries a load of 100 kW. The power factor at which the motor operates is ______
  1. 0.7

Open in App
Solution

The correct option is A 0.7
Load, P1=300kW,motor load=100kW
P.f. of load, cosϕ1=0.6 lagging
P.f. of load, cosϕ2=0.8 lagging
Combined load P=P1+P2=300+100=400kW
Leading kVAR taken by the motor
=P1tanϕ1P2tanϕ2
=300tan(cos10.6)400tan(cos10.8)
= 400 - 300 = 100 kVAR
Rating of the motor =(100)2+(100)2=141.42kVA
P.f of motor, cosϕm=100141.42=0.707 leading

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Problem Solving Using Newton's Laws
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon