Question

A system changes from the state $(p_1,v_1)$ to $(p_2,v_2)$ as shown in the diagram. The work done by the system is:

• A. $12\times {10}^{4}J$
• B. $12\times {10}^{8}J$
• C. $12\times {10}^{5}J$
• D. $6\times {10}^{4}J$

Answer 1

Answer: (C)

$12\times {10}^{5}J$

Work done by the system$=$Area under the line $(p_1{v}_1,p_2{v}_2)$$=$area of triangle + area of the small rectangle below the triangle
$W=0.5\left(4\right)\left(4\right)+\left(4\right)\left(1\right)=8+4=12$
i.e. $12\times {10}^{5}J$
Option C.