The work done in changing the state from ( $P_{0}, V_{0}$ ) to ( $P_{1}, V_{1}$ ) in the following system is:

- 7.5 \times 10^{- 5} J

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- 7.5 \times 10^{5} J

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- 7.5 \times 10^{5} e r g

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- 7.5 \times 10^{- 5} e r g

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Solution

The correct option is A $- 7.5 \times 10^{- 5} J$
Given- $P_{o} = 1 \times 10^{- 5} N m^{- 2}, P_{1} = 4 \times 10^{- 5} N m^{- 2}$
$V_{o} = 1 m^{3}, V_{1} = 4 m^{3}$

$W = - \int P △ V$ =Area under P-V Curve.
$= A r e a o f s q u a r e + A r e a o f t r i a n g l e$

$= P_{0} (V_{1} - V_{0}) + \frac{1}{2} (P_{1} - P_{0}) \times (V_{1} - V_{0})$

$= 7.5 \times 10^{- 5}$ N-m $O R$ Joules
Option A is correct.

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