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Question

A system consists of Block A and B of masses 5 kg each and connected to a pulley as shown in figure. Find the minimum value of force F at which they will start moving? (Assume g=10 m/s2).


A
60 N
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B
30 N
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C
120 N
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D
90 N
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Solution

The correct option is A 60 N
Let us find the forces acting on each block, so the FBDs of the blocks are as shown



From the FBDs we have
N1=5g=50 N
The static friction between block A and B is
f2s=μ2s(N1)=0.6(50)=30 N

Now, as per the question, the blocks just start moving, means, the friction will be limiting friction.

So, for block B:
T=f2s
For block A:
T+f2s=F
F=2f2s=2×30=60 N
Hence, if the force F is above 60 N, they will move.

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