Question

# Find the minimum value of force F for which the system remains at rest. Take g=10 m/s2.  60 N72 N80 N90 N

Solution

## The correct option is B 72 NThe FBDs of the system can be shown as: The 4 kg block will try to move towards right, so the frictional force f will act on it towards left. Thus, from the figure shown, we can write the equation of force as  (a) T=8g (b) T=F+f=F+μ(4g) From the above two equations we get ⇒8g=F+0.2×4×10 ⇒F=80−8=72 N

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