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Question

Find the minimum value of force F for which the system remains at rest. Take g=10 m/s2


  1. 60 N
  2. 72 N
  3. 80 N
  4. 90 N


Solution

The correct option is B 72 N
The FBDs of the system can be shown as:

The 4 kg block will try to move towards right, so the frictional force f will act on it towards left.

Thus, from the figure shown, we can write the equation of force as 
(a) T=8g
(b) T=F+f=F+μ(4g)
From the above two equations we get
8g=F+0.2×4×10
F=808=72 N

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