At A, amount of charge, qA= 2.5×10−7C (Given)
At B, amount of charge, qB=−2.5×10−7
Total charge of the system,
q=qA+qB=2.5×10−7C=0
Distance between two charges at points A and B,
d=15+15=30cm=0.3m
Electric dipole moment of the system is given by,
p=qA×d=2.5×10−7×0.3=7.5×10−8cm along positive z-axis.
Therefore, the electric dipole moment of the system is7.5×10−8 along the positive z-axis.