Question

A system is taken through a cycle process represented by a circle shown. The heat absorbed by the system is:

• A. $\pi \times {10}^{3}J$
• B. $\frac{\pi }{2}J$
• C. $4\pi \times {10}^{2}J$
• D. $\pi J$

Answer 1

The correct option is B $\frac{\pi }{2}J$

$\text{Solution}:$

Area of cyclic process = $\pi \frac{(150-50)\times {10}^3}{2}\times \frac{(40-20)}{2}\times {10}^{-6}=\frac{\pi }{2}J$

Work done is `+ve` and hence heat is absorbed.

$\text{Hence B is the correct option}$