Question

A system of three blocks are connected by strings as shown in figure. Calculate acceleration of each block and tension in the strings.

Answer 1

Common acceleration of the system is,

$6g-g=(6+3+1)a$

$a=\frac{60-10}{6+3+1}$

$a=5m{s}^2$

As they are connected to each other so, all blocks will have common acceleration.

Now,

For, $T_2$

$T_2-10=5$

$T_2=15N$

For $T_1$

$60-T_1=30$

$T_1=30N$