MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

First Law of Thermodynamics

A system unde...

Question

A system undergoes a process in which system releases 200 J heat and work done by the surroundings is 300 J. Change in internal energy of the system is

A

−100 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

100 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

−500 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

500 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
100 J

$Δ U = q + w$
Since system releases heat, q will be negative. It is also given that work done by the surroundings is 300 J which is the same as the work done on the system. Hence, w has a +ve sign. Keeping this in mind, we get:

= $- 200 + 300 = 100 J$

Suggest Corrections

thumbs-up

5

Similar questions

Q. A system undergoes a process in which system releases 200 J heat and workdone by the surroundings is 300 J. Change in internal energy of the system is

Q. A system undergoes a process in which system releases 200 J heat and work done by the surroundings is 300 J. Change in internal energy of the system is

Q. A system generates

50 J

of electrical energy, has

150 J

of pressure-volume work done on it by the surroundings while releasing

300 J

of heat energy. What is the change in the internal energy of the system?

Q. A system absorb

600 J

of heat and work equivalent to

300 J

on its surroundings. The change in internal is energy:

Q. In a certain process, 525 J of heat is absorbed by a system while 269 J of work is done on the system. What is the change in the internal energy for the process?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

First Law of Thermodynamics

CHEMISTRY

Watch in App

explore_more_icon

Explore more

First Law of Thermodynamics

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon