Question

$a-t$ graph for a particle moving in a straight line is as shown in figure.Change in velocity of the particle from $t=0$ to $t=6s$ is : (in m/s)

• A. $5$
• B. $4$
• C. $6$
• D. $3$

Answer 1

Answer: (B)

$4$

Area under the acceleration-time graph gives the change in velocity of the particle.
Area under the graph for $0\le t\le 6$, Area =$\frac{1}{2}\left(4\right)\left(4\right)-\frac{1}{2}\left(2\right)\left(4\right)=4m/s$
Thus change in velocity of particle $\Delta v=area=4m/s$