A T-V curve of a cyclic process is shown above, if the number of moles of the gas are n, find the total work done during the cycle
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Solution
Since path AB and CD are isochoric therefore work done is zero during
path AB and CD. Process BC and DA are isothermal, therefore WBC=nR2T0lnVCVB=2nRToln2 WDA=nRTolnVAVD=−nRTln2 Total work done =WBC+WDA=2nRToln2−nRToln2 =nRToln2