A tank is in the form of a right circular cylinder. Its height is 48 metre and the base area is 616 square metre . Find the lateral surface area and volume of the cylinder.

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Solution

Dear student,

$G i v e n, B a s e a r e a (A) = 616 m ² \Rightarrow π r ² = 616 \Rightarrow r ² = \frac{616}{π} ∴ r = \sqrt{\frac{616}{π}} S o, V o l u m e = π r ² h = π * \frac{616}{π} * 48 = 29, 568 m^{3} L a t e r a l s u r f a c e a r e a = 2 π r h = 2 π * \sqrt{\frac{616}{π}} * 48 = 4223.15 m ²$
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A tank is in the form of a right circular cylinder. Its height is 48 metre and the base area is 616 square metre . Find the lateral surface area and volume of the cylinder.

Dear student, Given, Base area (A) = 616 m²⇒πr² = 616 ⇒r² = 616π∴r = 616πSo, Volume = πr²h = π*616π*48 = 29,568 m3Lateral surface area = 2πrh = 2π*616π*48 = 4223.15 m² Regards