A tap can fill a tank in 24 hours and an outlet can empty the full tank in 30 hours. In how many hours the empty tank will be filled, if both the tap and the outlet are opened simultaneously ?

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Solution

Part of tank filled in 1hr. = 1/24^th
Part of tank emptied in 1 hr. = 1/30^th
If both are opened together
Part of tank filled in 1 hr.= $\frac{1}{24} - \frac{1}{30}$
$= \frac{30 - 24}{24 \times 30}$
$= \frac{6}{24 \times 30}$
$= \frac{1}{120} t h$
Time taken to fill the tank 120 hrs.

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A tap can fill a tank in 24 hours and an outlet can empty the full tank in 30 hours. In how many hours the empty tank will be filled, if both the tap and the outlet are opened simultaneously ?

Part of tank filled in 1hr. = 1/24th Part of tank emptied in 1 hr. = 1/30th If both are opened togetherPart of tank filled in 1 hr.= 124−130 =30−2424×30 =624×30 =1120th Time taken to fill the tank 120 hrs.

Part of tank filled in 1hr. = 1/24^th
Part of tank emptied in 1 hr. = 1/30^th
If both are opened together
Part of tank filled in 1 hr.= $\frac{1}{24} - \frac{1}{30}$
$= \frac{30 - 24}{24 \times 30}$
$= \frac{6}{24 \times 30}$
$= \frac{1}{120} t h$
Time taken to fill the tank 120 hrs.